0=2m^2+3m+7

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Solution for 0=2m^2+3m+7 equation: 



0=2m^2+3m+7

We move all terms to the left:

0-(2m^2+3m+7)=0

We add all the numbers together, and all the variables

-(2m^2+3m+7)=0

We get rid of parentheses

-2m^2-3m-7=0

a = -2; b = -3; c = -7;
Δ = b2-4ac
Δ = -32-4·(-2)·(-7)
Δ = -47
Delta is less than zero, so there is no solution for the equation

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